申请恢复:用的是正弦定理和二倍角公式:sinB cosc =- sinB(cos(B+A) =sinA (cosB)^2+sinBcosACOSB=-sinBCOSBCOSA+(sinB)^2sinA=sinA (cosB)^2+sinB cosA cosB=sinA[(COSb)^2-(SinB)^2]=2sinBcosBcosA-sinA COS2B=sinB COSA,-tanA=tan2B,-A=2B,2B+A=0,sin(2B+A)=0,2B+A=π,A+B+C=π.B-C=0,B=C.